Biomolecules Question 46
Question: The adjoining graph shows change in cone. Of substrate on enzyme activity. Identify A, B and C.
Options:
A) A - $ Ki $ B - $ K_{m} $ C - $ {V_{\max }} $
B) A - $ \frac{{V_{\max }}}{2} $ B - $ K_{m} $ C - $ Ki $
C) A - $ {V_{\max }} $ B - $ K_{m} $ C - $ \frac{{V_{\max }}}{2} $
D) A - $ K_{m} $ B - $ {V_{\max }} $ C - $ \frac{{V_{\max }}}{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
In the given graph which shows the change in the concentration of substrate on enzyme action activity, letter marked as A, B and C is respectively A - $ {V_{\max }} $ B - $ K_{m} $ C - $ \frac{{V_{\max }}}{2} $ . $ {V_{\max }} $ is the maximum velocity of the enzyme which determines the maximum speed of enzymatic reaction during which the substrate concentration is increased until a constant rate of product formation is achieved. This is called maximum velocity $ {V_{\max }} $ of the enzyme. K m , the Michaelis – Menten constant is the substrate concentration at which an enzyme attains half its maximal velocity.
BETA
