Evolution Of Life Question 42
Question: A population of organisms has a gene for which there are two alleles, D and d. The allele frequency of D = 0.8. If this population satisfies all five of the Hardy-Weinberg conditions, what are the genotype frequencies that are expected in the next generation?
Options:
A) DD = 0.04; Dd = 0.32; dd = 0.64
B) DD = 0.64; Dd = 0.32; dd = 0.64
C) DD = 0.04; Dd= 0.64; dd= 0.32
D) DD = 0.64; Dd = 0.32; dd = 0.04
Show Answer
Answer:
Correct Answer: D
Solution:
[d] We are told that the allele frequency for D = 0.8; therefore, the frequency of d= 0.2.
These values are the p and q that we need to calculate the genotype frequencies in the next generation.
Using the Hardy- Weinberg equation, $ P^{2} $ (DD) = 0.64, 2pq (Dd) = 0.32, and $ q^{2} $ (dd) = 0.04.
BETA
