Principle Of Inheritance And Variation Question 396
Question: The linkage map of X-chromosome of fruit fly has 66 units, with yellow body gene (y) at one end and bobbed hair [b] gene at the other end. The recombination frequency between these two genes (y and b) should be:
Options:
A) 100%
B) 66%
C) >50%
D) $ \le 50% $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Mapping of genes on chromosomes is based on the assumption that genes are arranged on the chromosome and that the percentage of crossing over (recombination frequency) between two genes is an index of their distance apart.
Distance between genes is expressed as map units, where, one map unit is defined as 1 per cent recombination.
BETA
