Principle Of Inheritance And Variation Question 454
Question: Given is : X is the chromosome with gene for haemophilia and X is the chromosome with normal gene. Which of the following individuals will act as carrier for haemophilia [MP PMT 1992]
Options:
A) $ X^{h}Y $
B) $ XY $
C) $ X^{h}X^{h} $
D) $ X^{h}X $
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Answer:
Correct Answer: D
Solution:
When both the chromosomes bear genes for disease i.e.
in homozygous condition, only then the character will be expressed otherwise the individual will act as a carrier.
BETA
