Alcohols Phenols And Ethers Question 105
Question: $ CH_3\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH=CH_2 $ $ \xrightarrow[(ii)H_2O_2/O{H^{-}}]{(i)B_2H_6}X\xrightarrow[140{}^\circ C]{H_2SO_4}Y. $ What is Y-
Options:
A) $ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_2-CH_2-O- $ $ CH_2-CH_2-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_3 $
B) $ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH=CH_2 $
C) $ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-O-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_3 $
D) $ CH_3-\underset{{}}{\mathop{\overset{CH_3}{\mathop{\overset{|}{\mathop{\underset{C_2H_5}{\mathop{\underset{|}{\mathop{C}}}}}}}}}}-O-\overset{CH_3}{\mathop{\overset{|}{\mathop{\underset{C_2H_5}{\mathop{\underset{|}{\mathop{C}}}}}}}}H-CH_3 $
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Answer:
Correct Answer: A
Solution:
[a] $ CH_2-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH=CH_2\xrightarrow[(ii)H_2O_2/O{H^{-}}]{(i)B_2H_6} $
$ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_2-\underset{OH}{\mathop{\underset{|}{\mathop{C}}}}H_2 $
$ \underset{(Y)}{\mathop{CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_2-\underset{{}}{\mathop{\underset{{}}{\mathop{C}}}}H_2-O-CH_2-CH_2-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-CH_3}} $
BETA
