Alcohols Phenols And Ethers Question 107
Question: $ CH_3-CH=CH_2\xrightarrow[(ii)NaBH_4]{(i)Hg{{(OAc)}_2}/H_2O}X+Na $ $ \xrightarrow{{}}Y+CH_3Cl\xrightarrow{{}}Z+HI\xrightarrow{0{}^\circ C}A+B $ What are A and B-
Options:
A) $ CH_3-CH_2-CH_2-OH\And CH_3I $
B) $ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-OH\And CH_3I $
C) $ CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H-I\And CH_3OH $
D) $ CH_3-CH_2CH_2I\And CH_3OH $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Going backward from A and B $ CH_3CH=CH_2\xrightarrow{{}}CH_3CH_2\underset{(X)}{\mathop{CH_2}}OH $
BETA
