Alcohols Phenols And Ethers Question 16
Question: The product A in the following reaction is $ \begin{matrix} H_2CCH_2 \\ \begin{aligned} & \\ & \overset{\backslash /}{\mathop{O}} \\ \end{aligned} \\ \end{matrix} \xrightarrow{RMgI}A $
[MP PMT 2003]
Options:
A) $ RCHOHR $
B) $ RCHOH\cdot CH_3 $
C) $ R-CH_2-CH_2-OH $
D) $ \begin{matrix} R \\ R \\ \end{matrix} >CHCH_2OH $
Show Answer
Answer:
Correct Answer: C
Solution:
$ CH_2=CH_2+RMgI\to \underset{OMgI}{\mathop{\underset{|}{\mathop{C}}H_2}}-CH_2-R\xrightarrow{HOH} $
$ MgI(OH)+R-CH_2-CH_2-OH $
BETA
