Alcohols Phenols And Ethers Question 207
Question: Acetyl bromide reacts with excess of $ CH_3MgI $ followed by treatment with a saturated solution of $ NH_4Cl $ gives
[AIEEE 2004]
Options:
A) 2-methyl-2-propanol
B) Acetamide
C) Acetone
D) Acetyl iodide
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{\text{Acetyl bromide}}{\mathop{CH_3-\overset{O}{\mathop{\overset{||}{\mathop{C}}}}-Br}}\underset{\text{(ii) Saturated }NH_4Cl}{\mathop{\xrightarrow{\text{(i) Excess-}CH_3MgI}}}\underset{\text{2-methyl 2-propanol}}{\mathop{CH_3-\underset{CH_3\ \ \ }{\overset{CH_3\ \ \ }{\mathop{\underset{|}{\overset{|}{\mathop{C}}}-OH}}}}} $
BETA
