Alcohols Phenols And Ethers Question 215
Question: $ C_6H_5-CH=CHCHO\xrightarrow{X}C_6H_5CH=CHCH_2OH $ . In the above sequence X can be
[DCE 2004]
Options:
A) $ H_2/Ni $
B) $ NaBH_4 $
C) $ K_2Cr_2O_7/{H^{+}} $
D) Both A and B
Show Answer
Answer:
Correct Answer: B
Solution:
$ NaBH_4 $ and $ LiAlH_4 $ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. $ \underset{\text{cinnamic aldehyde}}{\mathop{C_6H_5-CH=CHCHO}}\xrightarrow{NaBH_4} $
$ \underset{\text{cinnamic alcohol}}{\mathop{C_6H_5-CH=CH.CH_2OH}} $
BETA
