Aldehydes Ketones Question 12
Question: Propanal on reaction with dilute $ NaOH $ forms
Options:
A) $ CH_3CH_2CH_2CH_2CH_2CHO $
B) $ CH_3CH_2CH(OH)CH_2CH_2CHO $
C) $ CH_3CH_2CH_2CH(OH)CH_2CHO $
D) $ CH_3CH_2CH(OH)CH(CH_3)CHO $
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Answer:
Correct Answer: D
Solution:
[d] $ \underset{Propanal( 2molecules )}{\mathop{CH_3CH_2CHO+\overset{CH_3}{\mathop{\overset{|}{\mathop{C}}}}H_2\overset{O}{\mathop{\overset{||}{\mathop{C}}}}H\xrightarrow{dil.O{H^{-}}}}}\underset{\alpha }{\mathop{\overset{\beta CH_3}{\mathop{\overset{|}{\mathop{C}}}}}}H_2-\overset{OH}{\mathop{\overset{|}{\mathop{C}}}}H\overset{CH_3}{\mathop{\overset{|}{\mathop{C}}}}HCHO $ Note that it is the $ \alpha $ -carbon (and not $ \beta $ -) that is adding on the carbonyl oxygen of the other propanal molecule.
BETA
