A) $ CH_3CH( F )COOH $
B) $ FCH_2CH_2COOH $
C) $ BrCH_2CH_2COOH $
D) $ CH_3CH(Br)COOH $
Correct Answer: C
[c] Bromine is less electronegative than F, further in $ BrCH_2CH_2COOH $ , Br is more away from the - $ COOH $ group than in $ CH_3CHBrCOOH $ .
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