[IIT 1998]
A) $ CHCl_3 $
B) $ Cl_3CCHO $
C) $ CCl_4 $
D) $ ClCH_2CH_2Cl $
Correct Answer: B
$ CCl_3-CHO+H_2O\to \underset{(Chloralhydrate)}{\mathop{CCl_3.CHO.H_2O}}\to $
$ CCl_3.CH<\begin{matrix} OH \\ {} \\ OH \\ \end{matrix} $
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