Nitrogen Containing Compounds Question 69
Question: In the series of reaction $ C_6H_5NH_2\underset{0-5{}^\circ C}{\mathop{\xrightarrow{NaNO_2/HCl}}},X\underset{CH_2O}{\mathop{\xrightarrow{HNO_2}}},Y+N_2+HCl $ X and Y are respectively [EAMCET 2003]
Options:
A) $ C_6H_5-N=N-C_6H_5,,,C_6H_5N_2^{\oplus }C{{l}^{\Theta }} $
B) $ C_6H_5N_2^{\oplus }C{{l}^{\Theta }},,C_6H_5-N=N-C_6H_5 $
C) $ C_6H_5N_2^{\oplus }C{{l}^{\Theta }},,C_6H_5NO_2 $
D) $ C_6H_5NO_2,,C_6H_6 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ C_6H_5NH_2\underset{0^{o}C-5^{o}C}{\mathop{\xrightarrow{NaNO_2/HCl}}},\underset{\text{(X)}}{\mathop{C_6H_5N_2^{+}C{{l}^{-}}}},\underset{H_2O}{\mathop{\xrightarrow{HNO_2}}}, $ $ \underset{\text{(Y)}}{\mathop{C_6H_5NO_2}},+N_2+HCl $
BETA
