Nitrogen Containing Compounds Question 12
Question: $ RNH_2 $ reacts with $ C_6H_5SO_2Cl $ in aqueous $ KOH $ to give a clear solution. On acidification a precipitate is obtained which is due to the formation of [Roorkee 2000]
Options:
A) $ R-\underset{H,}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{{{N}^{+}}}}},}}},-SO_2C_6H_5O{{H}^{-}} $
B) $ R-{{N}^{-}}SO_2C_6H_5{{K}^{+}} $
C) $ R-NHSO_2C_6H_5 $
D) $ C_6H_5SO_2NH_2 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ C_6H_5SO_2Cl+RNH_2\to RNHSO_2C_6H_5\xrightarrow{KOH} $ $ \underset{\text{soluble in }KOH}{\mathop{RNKSO_2C_6H_5}}, $
BETA
