Analytical Chemistry Question 101
Question: If 20 ml of 0.25 N strong acid and 30 ml of 0.2 N of strong base are mixed, then the resulting solution is
[KCET 2002]
Options:
A) 0.25 N basic
B) 0.2 N acidic
C) 0.25 N acidic
D) 0.2 N basic
Show Answer
Answer:
Correct Answer: D
Solution:
$ V_1=20ml,N_1=0.25N,V_2=30ml $
$ N_2=0.2N $
$ \therefore N=\frac{N_1V_1+N_2V_2}{V_1+V_2}=\frac{20(0.25)+30(0.2)}{20+30} $
$ =\frac{5+6}{50}=\frac{11}{50}=0.2N $ basic
BETA
