Analytical Chemistry Question 122
Question: On passing $ H_2S $ black ppt. of II group is obtained. The mixture may not contain
[CPMT 1989]
Options:
A) $ P{b^{++}} $
B) $ C{d^{++}} $
C) $ H{g^{++}} $
D) $ C{u^{++}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ C{d^{++}}+H_2S\to \underset{\text{Yellow ppt}}{\mathop{CdS}}+H_2O $
BETA
