Analytical Chemistry Question 124
Question: Required amount of crystalline oxalic acid (eq. wt. = 63) to prepare $ {N}/{10}; $ 250 ml oxalic acid solution is
[MP PMT 1996]
Options:
A) 0.158 g
B) 1.575 g
C) 15.75 g
D) 6.3 g
Show Answer
Answer:
Correct Answer: B
Solution:
$ N\ =\ \frac{W _{B}\ \times \ 1000}{E\ \times \ V}\ \Rightarrow \ \frac{N}{10}\ =\ \frac{x\ \times \ 1000}{63\ \times 250} $
$ \therefore \ x\ =\ 1.575grams $
BETA
