Analytical Chemistry Question 170
Question: 0.45 g of acid (molecular weight 90) is neutralized by 20 ml of 0.5N caustic potash. The basicity of acid is
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Eq. of acid = Eq of base,
$ \therefore \frac{0.45}{E.wt}=\frac{20\times 0.5}{1000},=E.wt=45 $
$ Basicity=\frac{M.wt}{E.wt}=\frac{90}{45}=2 $
BETA
