Analytical Chemistry Question 196
Question: Volume of 3% solution of sodium carbonate necessary to neutralise a litre of 0.1N sulphuric acid
Options:
A) 176.66 ml
B) 156.6 ml
C) 116.0 ml
D) 196.1 ml
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Normality of 3% $ Na_2C{O_3} $ . $ N=\frac{3\times 100}{53\times 100}=0.566N $ For $ H_2SO_4sol.N_1=0.1,V_1=100mL $ For $ Na_2CO_3sol.N_2=0.566.N_2- $ Now apply $ N_1V_1=N_2V_2 $
$ V_2=\frac{N_1V_1}{N_2}=\frac{0.1\times 100mL}{0.566}=176.66mL $