Analytical Chemistry Question 2
Question: A substance on treatment with dil. $ H_2SO_4 $ liberates a colourless gas which produces
(I) turbidity with baryta water and (II) turns acidified dichromate solution green. The reaction indicates the presence of
Options:
A) $ CO_3^{2-} $
B) $ {s^{2-}} $
C) $ SO_3^{2-} $
D) $ NO_3^{-} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ Na_2SO_3+2HCl( dil )\to $
$ 2NaCl+H_2O+SO_2 $
$ K_2Cr_2O_7+H_2SO_4+3SO_2\to $
$ \underset{Green}{\mathop{K_2SO_4+Cr_2{{( SO_4 )}_3}+H_2O}} $
BETA
