Analytical Chemistry Question 200
Question: Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dil. $ NaCl $ solution and one formed a black precipitate with $ H_2S $ . The salt could be
Options:
A) $ AgNO_3 $
B) $ Pb{{( NO_3 )}_2} $
C) $ Hg{{( NO_3 )}_2} $
D) $ MnSO_4 $
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Answer:
Correct Answer: B
Solution:
[b] $ Pb{{(NO_3)}_2}+2NH_4OH\to $
$ \underset{( whiteppt )}{\mathop{Pb{{(OH)}_2}}}\downarrow +2NH_4NO_3 $
$ Pb{{(NO_3)}_2}+2HCl\to \underset{( whiteppt )}{\mathop{PbCl_2\downarrow }}+2HNO_3 $
$ Pb{{(NO_3)}_2}+H_2S\to \underset{( black )}{\mathop{PbS\downarrow }}+2HNO_3 $