Analytical Chemistry Question 201
Question: 0.45 g of an acid (mol wt. = 90) required 20 ml of 0.5 N $ KOH $ for complete neutralization. Basicity of acid is
[CPMT 1979]
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
Normality = N = $ \frac{W _{B}\ \times \ 1000}{Eq.wt\times V} $
$ \therefore \ Eq\text{.}\ Wt\ =\ \frac{0\text{.45}\ \times \ 1000}{0.5\ \times \ 20}\ =\ 45 $
$ \therefore \ Basicity\ =\ \frac{Molec\text{.}\ Wt}{Eq\text{. Wt}}\ =\ \frac{90}{45}\ =\ 2 $
BETA
