Analytical Chemistry Question 206
Question: 0.24 g of a volatile liquid on vaporization gives 45 ml of vapours at NTP. What will be the vapour density of the substance- (Density of $ H_2=0.089g{L^{-1}} $ )
Options:
A) 95.39
B) 39.95
C) 99.53
D) 59.93
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ V\text{.D}\text{.}=\frac{Wt.of45ml.ofvapoursatNTP}{Wt.of45ml.ofH_2atNTP} $
$ =\frac{0.24g}{45ml.\times 0.000089gm{l^{-1}}}=59.93 $
BETA
