Analytical Chemistry Question 208
Question: A gas “X” is passed through water to form a saturated solution. The aqueous solutions on treatment with the $ AgNO_3 $ gives a white preciptate. The saturated aqueous solution also dissolves magnesium ribbon with evolution of a colourless gas “Y” Identify ‘X’ and ‘Y-.
Options:
A) $ X=CO_2,Y=Cl_2 $
B) $ X=Cl_2,Y=CO_2 $
C) $ X=Cl_2,Y=H_2 $
D) $ X=H_2,Y=Cl_2 $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ Cl_2+H_2O\to HCl+HClO $
$ HCl+AgNO_3\to \underset{Whiteppt}{\mathop{AgCl\downarrow }}+HNO_3 $
$ Mg+2HCl\to MgCl_2+H_2\uparrow $ Hence X is $ Cl_2 $ and Y is $ H_2 $
BETA
