Analytical Chemistry Question 211
Question: Prussian blue is formed when
Options:
A) ferrous sulphate reacts with $ FeCl_3 $
B) ferric sulphate reacts with $ K_4Fe{{( CN )}_6} $
C) ferrous ammonium sulphate reacts with $ FeCl_3 $
D) ammonium sulphate reacts with $ NO_2 $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ 2Fe_2{{(SO_4)}_3}+3K_4[(Fe{{(CN)}_6}]\to $
$ \underset{Prussianblue}{\mathop{Fe_4{{[Fe{{( CN )}_6}]}_3}}}+6K_2SO_4 $
BETA
