Analytical Chemistry Question 214
Question: An organic compound has C and H percentage in the ratio 6 : 1 and C and O percentage in the ratio 3:4 the compound is
Options:
A) HCHO
B) $ CH_3OH $
C) $ CH_3CH_2OH $
D) $ {{(COOH)}_2} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] % ratio of $ C:H $ is $ 6:1 $ and $ C:O $ is $ 3:4 $ or 6:8
$ \therefore $ % ratio of $ C:H:Ois6:1:0 $ (Total =15) % of $ C=\frac{6}{15}\times 100=40 $ 40/12=3. 33=1 % of $ H=\frac{1}{15}\times 100=6.6 $ 6.6/1=6.6=2 % of $ O=\frac{8}{15}\times 100=53.3 $ 53.3/16=3.3=1 simple ratio: $ CH_2O $
$ \therefore $ The compound is HCHO
BETA
