Analytical Chemistry Question 217
Question: The equivalent weight of KMnO4 in alkaline medium will be
[MP PMT 2001]
Options:
A) 31.60
B) 52.66
C) 79.00
D) 158.00
Show Answer
Answer:
Correct Answer: D
Solution:
$ \overset{+7}{\mathop{KMnO_4}}\to \overset{+6}{\mathop{K_2MnO_4}} $
$ \frac{Molecularweight}{1}=\frac{158}{1}=158 $