Analytical Chemistry Question 217

Question: The equivalent weight of KMnO4 in alkaline medium will be

[MP PMT 2001]

Options:

A) 31.60

B) 52.66

C) 79.00

D) 158.00

Show Answer

Answer:

Correct Answer: D

Solution:

$ \overset{+7}{\mathop{KMnO_4}}\to \overset{+6}{\mathop{K_2MnO_4}} $

$ \frac{Molecularweight}{1}=\frac{158}{1}=158 $