Analytical Chemistry Question 227
Question: 20 ml of a solution of a weak monobasic acid neutralizes 22.18 ml of a solution of NaOH and 20 ml of N/10 HCl neutralizes 21.5 ml of the same NaOH solution. The normality for the acid is nearly
[MP PET 2002]
Options:
A) 10 N
B) 1 N
C) 0.10 N
D) 100 N
Show Answer
Answer:
Correct Answer: C
Solution:
$ N_1V_1=N_2V_2 $
$ N_1\times 20=N_2\times 22.18 $
$ N_1=\frac{N_2\times 22.18}{20} $ —(i) $ NaOH $ solution = $ HCl $ solution $ N_2\times 21.5=\frac{1}{10}\times 20 $
$ N_2=\frac{20}{10\times 21.5} $ –.(ii) by eq. (i) and (ii) $ N_1=\frac{20\times 22.18}{20\times 10\times 21.5}=\frac{22.18}{215}=0.1N $
BETA
