Analytical Chemistry Question 229
Question: How many grams of $ NaOH $ are equivalent to 100 ml of 0.1 N oxalic acid
Options:
A) 0.2
B) 2.0
C) 0.4
D) 4.0
Show Answer
Answer:
Correct Answer: C
Solution:
$ N\ =\ \frac{W _{B}\ \times \ 1000}{Eq\text{.}wt\text{.}\ \times \ V};\ W _{B}=\frac{N\times \ Eq.wt\ \times \ V}{1000} $
$ =\frac{0.1\times 40\times 100}{1000}=0.4 $
BETA
