Analytical Chemistry Question 23
Question: …….. is formed when potassium iodide is heated with conc. $ H_2SO_4 $
[CPMT 1971]
Options:
A) $ HI $
B) $ I_2 $
C) $ HIO_3 $
D) $ KIO_3 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ 2KI+2H_2SO_4\ (Conc\text{.)}\ \to 2KHSO_4\ +\ 2HI $
$ MnO_2+H_2SO_4\to MnSO_4+H_2O+(O) $
$ 2HI+(O)\to H_2O+I_2 $
$ 2KI+MnO_2+3H_2SO_4\to I_2+MnSO_4+2H_2O $
$ +2KHSO_4 $
BETA
