Analytical Chemistry Question 230
Question: 0.126 g of an acid requires 20 ml of 0.1 N NaOH for complete neutralization. The equivalent weight of the acid is
[MP PET 2001]
Options:
A) 45
B) 53
C) 40
D) 63
Show Answer
Answer:
Correct Answer: D
Solution:
20 ml of 0.1N $ NaOH $ neutralize 20 ml of 0.1N acid $ Weightofacid=0.126g $ Volume = 20 ml= $ \frac{20}{1000}litre $ Normality = 0.1 N Equivalent weight = - $ Equivalentweight=\frac{weightofacid}{N\times V} $
$ =\frac{0.126\times 1000}{0.1\times 20}=63 $
BETA
