Analytical Chemistry Question 231
Question: The equivalent weight of a divalent metal is 31.82. The weight of a single atom is
[MH CET 2000]
Options:
A) $ 63.64 $
B) $ \frac{63.64}{6.02\times 10^{23}} $
C) $ 32.77\times 6.02\times 10^{23} $
D) $ 63.64\times 6.02\times 10^{23} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ 2\times 31.82 $ ,
$ \therefore $ wt of one atom $ =\frac{2\times 31.82}{N}=\frac{63.64}{N} $