Analytical Chemistry Question 231

Question: The equivalent weight of a divalent metal is 31.82. The weight of a single atom is

[MH CET 2000]

Options:

A) $ 63.64 $

B) $ \frac{63.64}{6.02\times 10^{23}} $

C) $ 32.77\times 6.02\times 10^{23} $

D) $ 63.64\times 6.02\times 10^{23} $

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Answer:

Correct Answer: B

Solution:

$ 2\times 31.82 $ ,
$ \therefore $ wt of one atom $ =\frac{2\times 31.82}{N}=\frac{63.64}{N} $