Analytical Chemistry Question 237
Question: 2.79 g of an organic compound when heated in Carius tube with cone. $ HNO_3 $ and $ H_2PO_4 $ formed is converted into $ MgNH_4.PO_4 $ ppt. The ppt. on heating gave 1.332 g of $ Mg_2P_2O_7 $ . The percentage of P in the compound is
Options:
A) 23.33%
B) 13.33%
C) 33.33%
D) 26.66%
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Percentage of P $ =\frac{62}{222}\times \frac{wt.ofMg_2P_2O_7}{wt.ofcompound}\times 100 $
$ =\frac{62}{222}\times \frac{1.332}{2.79}\times 100=13.33% $ %
BETA
