Analytical Chemistry Question 240
Question: 0.16 gm of a dibasic acid required 25 ml of decinormal $ NaOH $ solution for complete neutralization. The molecular weight of the acid is
[CPMT 1989; MP PET 1993]
Options:
A) 32
B) 64
C) 128
D) 256
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Answer:
Correct Answer: C
Solution:
$ \frac{0.16}{x}\ \times \ \frac{1000}{25}\ =\ \frac{1}{10} $
Þ $ \frac{6.4}{x}\ =\ \frac{1}{10}\ \ \ \ \therefore \ x\ =\ 64 $ Mol. wt. = 64 × 2 = 128
BETA
