Analytical Chemistry Question 242
Question: 0.1914g of an organic acid is dissolved in approx. 20 ml of water. 25 ml of 0.12 N NaOH required for the complete neutralization of the acid solution. The equivalent weight of the acid is
[MP PET 2000]
Options:
A) 65
B) 64
C) 63.80
D) 62.50
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Answer:
Correct Answer: C
Solution:
$ Volume=25ml=\frac{25}{1000}litre $
$ Normality=\frac{wt}{eq.wt\times Volume} $ Þ $ 0.12=\frac{0.1914\times 1000}{E\times 25} $
$ eq.wt.=\frac{0.1914\times 1000}{0.12\times 25}=63.8 $
BETA
