Analytical Chemistry Question 250
Question: What will be the volume of $ CO_2 $ at S.T.P., obtained by heating 9.85 g of $ BaCO_3 $ (Atomic number of $ Ba $ = 137)
[MP PMT 2003]
Options:
A) 1.12 litre
B) 0.84 litre
C) 2.24 litre
D) 4.06 litre
Show Answer
Answer:
Correct Answer: A
Solution:
$ BaCO_3\to BaO+CO_2\uparrow $
$ \therefore 197gBaCO_3 $ on decompose gives = 22.4 litre $ CO_2 $
$ \therefore 1gBaCO_3 $ will give = $ \frac{22.4}{197}=litreCO_2 $
$ =\frac{22.4\times 9.85}{197}=1.12litreCO_2 $
BETA
