Analytical Chemistry Question 267
Question: To neutralise 10 ml of $ {M}/{5}; $ $ NaOH $ the volume of $ {M}/{20}; $ $ HCl $ required is
[EAMCET 1980]
Options:
A) 10 ml
B) 15 ml
C) 40 ml
D) 25 ml
Show Answer
Answer:
Correct Answer: C
Solution:
$ N_1V_1=N_2V_2 $
Þ $ \frac{1}{5}\ \times 10\ =\ \frac{1}{20}\ \times \ V_2\ \Rightarrow \ V_2\ =\ 40\ ml $
BETA
