Analytical Chemistry Question 268
Question: To change the strength of 25 ml of 0.15 M $ HCl $ to 0.1 M the quantity of water that is to be added is
[EAMCET 1979]
Options:
A) 37.5 ml
B) 12.5 ml
C) 25.0 ml
D) 18.75 ml
Show Answer
Answer:
Correct Answer: B
Solution:
$ N_1V_1\ =\ N_2V_2 $
$ 0.15\times 25=0.1V_2\Rightarrow V_2=37.5ml $ Water to be added = 37.5 - 25 = 12.5 ml