Analytical Chemistry Question 268

Question: To change the strength of 25 ml of 0.15 M $ HCl $ to 0.1 M the quantity of water that is to be added is

[EAMCET 1979]

Options:

A) 37.5 ml

B) 12.5 ml

C) 25.0 ml

D) 18.75 ml

Show Answer

Answer:

Correct Answer: B

Solution:

$ N_1V_1\ =\ N_2V_2 $

$ 0.15\times 25=0.1V_2\Rightarrow V_2=37.5ml $ Water to be added = 37.5 - 25 = 12.5 ml



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