Analytical Chemistry Question 273
Question: What is the volume of 0.1 N-HCl required to react completely with 1.0 gm of pure calcium carbonate-
[DPMT 2004]
Options:
A) $ 100cm^{3} $
B) $ 150cm^{3} $
C) $ 250cm^{3} $
D) $ 200cm^{3} $
Show Answer
Answer:
Correct Answer: D
Solution:
Given, $ N=0.1, $ w = 1.0 gm, equivalent weight = 50, V = - $ V=\frac{w\times 1000}{Eq.wt.\times N}=\frac{1\times 1000}{50\times 0.1}=200\ cm^{3} $
BETA
