Analytical Chemistry Question 278
Question: The volume of $ \frac{N}{10} $ NaOH require to neutralise 100 ml of $ \frac{N}{25} $ HCl is
[Pb. CET 2000]
Options:
A) 30 ml
B) 100 ml
C) 40 ml
D) 25 ml
Show Answer
Answer:
Correct Answer: C
Solution:
For complete neutralisation, milli equivalent of base = milli equivalent of acid $ N_1V_1=N_2V_2 $ Þ $ \frac{1}{10}\times V_1=\frac{1}{25}\times 100 $ ; $ V_1=40\ ml. $
BETA
