Analytical Chemistry Question 281
Question: An orange precipitate of II group is dissolved in cone. $ HCl $ ; the solution when treated with excess of water turns milky due to formation of
Options:
A) $ Sn( OH )Cl $
B) $ Sb( OH )Cl_2 $
C) $ SbOCl $
D) $ Sb{{( OH )}_2}Cl $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ Sb_2S_3+6HCl\to 2SbCl_3+3H_2S $
$ SbCl_3+6H_2O\to \underset{ppt( White )}{\mathop{SbOCl}}+2HCl $
BETA
