Analytical Chemistry Question 30
Question: When $ KBr $ is treated with conc. $ H_2SO_4 $ a reddish-brown gas is evolved. The evolved gas is
[EAMCET 1978]
Options:
A) Bromine
B) Mixture of bromine and $ HBr $
C) $ HBr $
D) $ NO_2 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ 2KBr+MnO_2+3H_2SO_4\to MnSO_4+2KHSO_4 $
$ +2H_2O+\underset{\begin{smallmatrix} \text{(reddish} \\ \text{brown gas)} \end{smallmatrix}}{\mathop{Br_2\uparrow }} $
BETA
