Analytical Chemistry Question 30
When $ KBr $ is treated with conc. $ H_2SO_4 $ a reddish-brown gas is evolved. The evolved gas is bromine vapour (Br₂)
[EAMCET 1978]
Options:
A) Bromine
B) Mixture of bromine and $ HBr $
C) $ HBr $
D) $ NO_2 $
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Answer:
Correct Answer: A
Solution:
$ 2KBr+MnO_2+3H_2SO_4\to MnSO_4+KHSO_4+Br_2+H_2O $
$ +2H_2O+\underset{\begin{smallmatrix} \text{(reddish} \\ \text{brown gas)} \end{smallmatrix}}{\mathop{Br_2\uparrow }} $
BETA
