Atomic Structure Question 1
Question: The ionisation potential of a hydrogen atom is +13.6 eV. What will be the energy of the atom corresponding to $ n=2 $ [Pb. CET 2000]
Options:
A) 3.4 eV
B) 6.8 eV
C) 1.7 eV
D) 2.7 eV
Show Answer
Answer:
Correct Answer: A
Solution:
Energy of an electron $ E=\frac{-E_0}{n^{2}} $ For energy level $ (n=2) $
$ E=-\frac{13.6}{{{(2)}^{2}}}=\frac{-13.6}{4}=-3.4eV $ .
BETA
