Atomic Structure Question 155
Question: For principle quantum number $ n=4 $ the total number of orbitals having $ l=3 $
[AIIMS 2004]
Options:
3
7
5
9
Show Answer
Answer:
Correct Answer: B
Solution:
$ n=4,\to 1s^{2},,2s^{2},,2p^{6},,3s^{2},,3p^{6},,3d^{10},,4s^{2},,4p^{6},,4d^{10},,4f^{14} $ So $ l=(n-1)=4-1=3 $ which is f orbit contains 7 orbitals.
BETA
