Atomic Structure Question 212
Question: The total number of valence electrons in $ 4.2,gm $ of $ N_3^{-} $ ion is ( $ N_{A} $ is the Avogadro’s number) [CBSE PMT 1994]
Options:
A) $ 1.6N_{A} $
B) $ 3.2N_{A} $
C) $ 2.1N_{A} $
D) $ 4.2N_{A} $
Show Answer
Answer:
Correct Answer: A
Solution:
42g of $ N_3^{-} $ ions have $ 16,N_{A} $ valence electrons 4.2g of $ N_3^{-} $ ion have $ =\frac{16,N_{A}}{42}\times 4.2=1.6,N_{A} $ .
BETA
