Atomic Structure Question 242
Question: If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom, the total energy of the revolving electron will be:
Options:
A) $ \frac{1}{2}\frac{e^{2}}{r} $
B) $ -\frac{e^{2}}{r} $
C) $ \frac{me^{2}}{r} $
D) $ -\frac{1}{2}\frac{e^{2}}{r} $
Show Answer
Answer:
Correct Answer: D
Solution:
- Total energy of a revolving electron is the sum of its kinetic and potential energy. Total energy $ =K.E.+P.E. $
$ =\frac{e^{2}}{2r}+( -\frac{e^{2}}{r} )=-\frac{e^{2}}{2r} $
BETA
