Atomic Structure Question 243
Question: Excited hydrogen atom emits light in the ultraviolet region at $ 2.47\times 10^{15}Hz $ . With this frequency, the energy of a single photon is: $ (h=6.63\times {10^{-34}}Js) $
Options:
A) $ 8.041\times {10^{-40}}J $
B) $ 2.680\times {10^{-19}}J $
C) $ 1.640\times {10^{-18}}J $
D) $ 6.111\times {10^{-17}}J $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ E=hv $
$ =6.63\times {10^{-34}}\times 2.47\times 10^{15} $
$ =1.640\times {10^{-18}}J $
BETA
