Atomic Structure Question 30
Question: The quantum numbers for the outermost electron of an element are given below as $ n=2,,l=0,,m=0,,s=+\frac{1}{2} $ . The atoms is [EAMCET 1978]
Options:
A) Lithium
B) Beryllium
C) Hydrogen
D) Boron
Show Answer
Answer:
Correct Answer: A
Solution:
The electronic configuration must be $ 1s^{2},2s^{1}. $
Hence, the element is lithium $ (z=3). $
BETA
