Atomic Structure Question 301
Question: The frequency of one of the lines in Paschen series of hydrogen atom is $ 2.340\times 10^{11}Hz. $ The quantum number $ n_2 $ which produces this transition is
[DPMT 2001]
Options:
6
5
4
3
Show Answer
Answer:
Correct Answer: B
Solution:
$ \overline{\nu }=\frac{1}{\lambda }=R_{H}\left[ \frac{1}{n_1^{2}}-\frac{1}{n_2^{2}} \right] $
$ =\frac{1}{\lambda }=R_{H}[ \frac{1}{3^{2}}-\frac{1}{n_2^{2}} ]=n_2>3 $ for Paschen series.
BETA
