Atomic Structure Question 305
Question: If the subsidiary quantum number of a subenergy level is 4, the maximum and minimum values of the spin multiplicities are:
Options:
A) 9, 1
B) 10, 1
C) 10, 2
D) 4,- 4
Show Answer
Answer:
Correct Answer: C
Solution:
- $ l=4; $ number of degenerate orbitals $ =2l+1=9; $ maximum total spins $ =9\times \frac{1}{2} $ maximum multiplicity $ =2s+1 $
$ =2\times \frac{9}{2}+1=10 $ minimum total spins $ =\frac{1}{2} $ minimum multiplicity $ =2\times \frac{1}{2}+1=2 $
BETA
